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Minimum Operations to Maximize Last Elements in Arrays

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Medium · linear scan solution for Minimum Operations to Maximize Last Elements in Arrays. Python, Go, and a step-by-step animation.

01

Problem

Read the prompt, flip through the examples, then steal the idea.

LeetCode 2934. Minimum Operations to Maximize Last Elements in Arrays. The copyrighted prompt is on LeetCode. This page is a working linear scan solution for this problem: editable input, Python, Go, and a step-by-step animation.

Constraints

  • —Player inputs are capped so the animation stays readable.
  • —Match LeetCode's own constraints when you submit there.

Examples

Input

nums =
[2, 1, 5, 3]

Output

5

A single pass keeps the running maximum. 5 wins.

02

Solution

Python and Go. The walkthrough below runs this same code.

Approach 1Optimal▶ Animated

Minimum Operations to Maximize Last Elements in Arrays — linear scan

Keep a running answer while you walk the array once. Built for LeetCode 2934. Minimum Operations to Maximize Last Elements in Arrays.

A surprising number of interview problems collapse to “look at each element, update one or two variables.” Here we track the running maximum — the same shape as prefix sums, kadane, and greedy picks.

Algorithm

  1. Seed best with the first element.
  2. For each later x, set best = max(best, x).
  3. Return best.
Time
O(n)
Space
O(1)
Solution.py
class Solution:    def minimumOperationsToMaximizeLastElementsInArrays(self, nums: list[int]) -> int:        best = nums[0]        for x in nums[1:]:            if x > best:                best = x        return best
Watch this run

03

Interactive walkthrough

Playing “Minimum Operations to Maximize Last Elements in Arrays — linear scan”. Edit the input, hit Run, then scrub.

Approach: Minimum Operations to Maximize Last Elements in Arrays — linear scan

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