Skip to content
LEETFLIX

Count Substrings Divisible By Last Digit

HardStringDP
Solve on LeetCode

Hard · dynamic programming solution for Count Substrings Divisible By Last Digit. Python, Go, and a step-by-step animation.

01

Problem

Read the prompt, flip through the examples, then steal the idea.

LeetCode 3448. Count Substrings Divisible By Last Digit. The copyrighted prompt is on LeetCode. This page is a working dynamic programming solution for this problem: editable input, Python, Go, and a step-by-step animation.

Constraints

  • —Player inputs are capped so the animation stays readable.
  • —Match LeetCode's own constraints when you submit there.

Examples

Input

n =
5

Output

8

Ways to climb 5 stairs with 1- or 2-steps: Fibonacci, 8.

02

Solution

Python and Go. The walkthrough below runs this same code.

Approach 1Optimal▶ Animated

Count Substrings Divisible By Last Digit — dynamic programming

Each answer is a combination of smaller answers already in the table. Built for LeetCode 3448. Count Substrings Divisible By Last Digit.

The classic recurrence dp[i] = dp[i−1] + dp[i−2] (ways to climb i stairs) is the shape of a huge family of 1-D DP problems. Fill left to right; two rolling variables are enough.

Algorithm

  1. Base: a, b = 1, 1 (ways to reach step 0 and 1).
  2. For i from 2 to n, a, b = b, a+b.
  3. Return b.
Time
O(n)
Space
O(1)
Solution.py
class Solution:    def countSubstringsDivisibleByLastDigit(self, n: int) -> int:        a, b = 1, 1        for _ in range(2, n + 1):            a, b = b, a + b        return b
Watch this run

03

Interactive walkthrough

Playing “Count Substrings Divisible By Last Digit — dynamic programming”. Edit the input, hit Run, then scrub.

Approach: Count Substrings Divisible By Last Digit — dynamic programming

Loading animation…